Question

If n = 10^10 – 1, the number of digit in n^3 is

Answer 1

Given: n = 10^10 – 1

To find: Number of digits in n^3

Answer:

n = 10^10 – 1 = 10000000000 - 1 = 9999999999 (Two digits)

n = 99

Therefore n^3 = (9999999999)^3 = 1e + 30 (Thirty Digits)

Hope it helps :)