Question

If n(ξ) = 120, n(A’) = 60,n(B) = 70, and n(AՈB) = 20, find n((AUB)’)

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Answer 1

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

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