Question

If n=2^3×3^4×5^4×7 , then find the number of consecutive zeroes in n,where 'n' is a natural number.

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Answer 1

Answer:

here you go

Step-by-step explanation:

zeroes at the end of a number are only formed if the number has BOTH 2 and 5 as it's prime factors, whatever the number be. just combine their power and that's your answer

Answer 2

Answer:

1000

Step-by-step explanation:

I HOPE YOU UNDERSTOOD