Physics, asked by homasree58, 9 months ago

Some rays falling on a converging lens are
focused 20 cm from the lens. When a
diverging lens is placed in contact with the
converging lens, the rays are for 30 cm from
the combination. What is the focal length of
the diverging lens.
(a)50cm

(b)-50cm

(c)-60cm
(d60cm​

Answers

Answered by nirman95
4

Given:

Parallel rays falling on converging lens are focused at 20 cm from the lens. When a diverging lens is added , the rays are focused at 30 cm from the combination.

To find:

Focal length of diverging lens.

Calculation:

Since the parallel rays upon reflection are getting focussed at a particular distance from the lens , we can consider that distance to be the focal length of the lens.

Therefore , focal length of convex lens alone is 20 cm.

And , focal length of combination of lens is 30 cm.

Let focal length of diverging lens be f_{2}

Applying Formula for Combination Of Lens:

 \therefore \:  \bold{ \dfrac{1}{f_{eff.}}  =  \dfrac{1}{f_{1}}  +  \dfrac{1}{f_{2}} }

  =  >  \:  \dfrac{1}{( + 30)}  =  \dfrac{1}{( + 20)}  +  \dfrac{1}{f_{2}}

  =  >  \:  \dfrac{1}{f_{2}}  =  \dfrac{1}{30}  -  \dfrac{1}{20}

  =  >  \:  \dfrac{1}{f_{2}}  =  \dfrac{2 - 3}{60}

  =  >  \:  \dfrac{1}{f_{2}}  =  \dfrac{ - 1}{60}

  =  >  \:  f_{2} =   - 60 \: cm

So , focal length of concave (diverging) lens is -60 cm. Negative value of this type of lens verifies our value.

{\boxed{\bold{\red{\huge{Option \: C}}}}}

Answered by knjroopa
0

Explanation:

Given Some rays falling on a converging lens are focused 20 cm from the lens. When a  diverging lens is placed in contact with the  converging lens, the rays are for 30 cm from  the combination. What is the focal length of  the diverging lens.

  • According to the question we have
  • So focal length of converging lens f1 = 20 cm
  • We need to find the focal length of diverging lens f2  
  • Given rays are 30 cm from the combination so focal length of the combination  f = 30 cm
  • So 1/f = 1/f1 + 1/f2
  •    1/30 = 1/20 + 1/f2
  •   1/30 – 1/20 = 1/f2
  •   2 – 3 / 60 = 1/f2
  • So – 1/60 = 1/f2
  • Or f2 = - 60 cm
  • Therefore focal length of the diverging lens is – 60 cm

Reference link will be

https://brainly.in/question/13925721

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