Math, asked by nabihaumaima, 3 months ago

if n-2y=3y+n/m, find the value of n when y=-4 and m=5​

Answers

Answered by Anonymous
1

Step-by-step explanation:

given \:  \: y =  - 4 \:  \:  \:  \: m = 5 \\ n - 2y = 3y +  \frac{n}{m}  \\   n  - 2( - 4) = 3( - 4) +  \frac{n}{5}  \\  n  +  8 =  - 12 +  \frac{n}{5}  \\  n + 8 =  \frac{ - 60 + n}{5}  \\  5n + 40 =  - 60 + n \\ 5n - n =  - 60 - 40 \\ 4n =  - 100 \\ n = -25

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Answered by itzcottoncandy65
32

If y = -4 and m = 5 put them in the equation that is -

= n -2(-4) = 3(-4) + n/5

= n + 8 = -12 + n/5

= n + 8 + 12 = n/5

= n + 20 = n/5

= n * n = 5 * 20

= n² = 100

= n = √100

= n = 10

∴ n = 10

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