Question

If n-2y =
$\frac{3y +n}{m}$
, find the value of n when y = -4 and m = 5.​

Answer 1

Step-by-step explanation:

At first we can try to find the difference between two consecutive terms which is

(x−y)–(x+y)=−2y

So after that we can understand the third and forth terms in terms of x and y.

They can be : (x−3y) and (x–5y)

Now try to do rest of the sum………………………………..

Second Hint

If you got stuck after the first hint you can use this :

Though we from our solution we find the other two terms to be (x−3y) and (x−5y)

but from the question we find that the other two terms are xy and xy

So both are equal.Thus ,

xy=x–3y

xy–x=–3y

x(y–1)=−3y

x=−3yy–1 ……………………………(1)

Again , similarly

xy=x−5y

Now considering the equation (1) we can take the value of xy

−3y–1=−3yy−1–5y …………………….(2)

−3=−3y–5y(y−1)

0=5y2–2y–3

0=(5y+3)(y−1)

y=–35,1

We are almost there with the answer. Try to find the answer…..

Final Step

Now from the last hint we find the value of y=–35,1

But we cannot consider the value of y to be 1 as the 1st and 2 nd terms would be x+1 and x−1) but last two terms will be equal to x .

So the value of y be −35 and substituting the value of y in either eqn (1) or eqn (2) we get x = -98

so , xy−2y=9.58.3+65

= 12340 (Answer )

Answer 2

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Given: y= -4, m=5

$\sf \: n - 2y = \frac{3y + n}{m}$

Put the values of y and m

$\sf \: n - 2 ( - 4) = \frac{3 ( - 4) + n}{5} \\ \\ \implies \sf \: n + 8 = \frac{ - 12 + n}{5} \\ \\ \implies \sf \: \frac{n \times 5}{n} = - 12 - 8 \\ \\ \sf \implies \frac{ \cancel{5n}}{ \cancel n} = - 16 \\ \\ \implies \sf \: 4n = - 16 \\ \\ \sf \: n = \frac{ - 16}{4} = - 4$

So n= -4

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