Question

Sum of two numbers is $\dfrac{3}{4}$ ,one of the number is $\dfrac{1}{8}$ find the other..​

Answer 1

Answer:

Let the other number be x

$\implies$ x + $\dfrac{1}{8 }$ = $\dfrac{3}{4}$

$\blue{\bold{\underline{\underline{}}}}$

$\implies$ x = $\dfrac{3}{4}$ - $\dfrac{1}{8}$

$\blue{\bold{\underline{\underline{}}}}$

$\implies$ x = $\dfrac{3 × 2}{4 × 8}$ - $\dfrac{1}{8}$

$\blue{\bold{\underline{\underline{}}}}$

$\implies$ x = $\dfrac{6}{8}$ - $\dfrac{1}{8}$

$\blue{\bold{\underline{\underline{}}}}$

$\implies$ x = $\dfrac{6 - 1}{8}$

$\blue{\bold{\underline{\underline{}}}}$

$\implies$ x = $\dfrac{5 }{8}$

Answer 2

If one number is 1 then other number
—
8
is 7
—
8