If n=3 mention the orbital present in the shell and write maximum number of electron in the shell
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Given,
Principal Quantum number (n) = 3
Thus, The Possible values of 'l' (Azimuthal Quantum number) is 0,1,2.
Now, From this we can determine the numbers of Orbitals in each orbits.
∴ 0 = 1 Orbital = 2 Electrons. [s-orbital]
1 = -1,0,1 = 3 Orbital = 3 × 2 = 6 electrons. [p-orbital]
2 = -2,-1,0,1,2 = 5 Orbital = 5 × 2 = 10 electrons. [d-orbital]
Total numbers of the Electrons = 2 + 6 + 10 = 18 electrons.
Hope it helps.
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