if n= 5 q + 4 then check whether n×n -1 is divisible by 5 for some integer q.
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Answered by
10
n = 5q +4
n*n-1 = (5q +4) (5q +4) -1
= 25q^2 + 40q + 16 -1
= 25q^2 + 40q + 15
by taking the common factor out,
5 (5q^2 + 8q +3)
So it's a multiple of 5.
therefore it is divisible by 5 for all integers q.
p.s. mark me as brainliest!!!!
n*n-1 = (5q +4) (5q +4) -1
= 25q^2 + 40q + 16 -1
= 25q^2 + 40q + 15
by taking the common factor out,
5 (5q^2 + 8q +3)
So it's a multiple of 5.
therefore it is divisible by 5 for all integers q.
p.s. mark me as brainliest!!!!
Answered by
2
Answer:
n=5q+4
n2-1=(5q+4)(5q+4)-1
n2-1=25q2+40q+16-1
n2-1=25q2+40q+15
now,
factorize 25q2+40q+15
=5(5q2+8q+3)
this is the multiple of 5
so,
it is divisible by 5
hence checked
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