Question

If n = 6, the correct sequence for filling of electrons will be :
(a) ns → (n – 2) f → (n – 1) d → np
(b) ns → (n – 1) d → (n – 2) f → np
(c) ns → (n – 2) f → np → (n – 1) d
(d) ns → np → (n – 1) d → (n – 2) f

Answer 1

d) ns → np → (n – 1) d → (n – 2) f is the correct order of filling

Answer 2

If n = 6, the correct sequence for filling of electrons will be  

ns → (n – 2) f → (n – 1) d → np.

Explanation:

• ns → (n – 2) f → (n – 1) d → np is the correct sequence for n = 6, when electrons are filled 6s→ (6-2) f→ (6-1) d→6p.
• 6s→4f→5d→6p .
• In the increasing order the electrons are filled during ground state.
• The orbitals are filled using sequence of value increased by (n+l).

1. 6+0 = 6 for orbital of 6s,
2. 4+3 = 7 for orbital of 4f,
3. 5+2 = 7 for orbital of 5d,
4. 6+1 = 7 for orbital of 6p.

• (n+l) value is equal for both the orbitals, first the lowest value of n will be filled.

Aufbau principle

• The addition electrons to orbitals as the addition of protons to an atom.
• The lowest electron orbitals are filled first after that highest electron orbitals are filled.  

• Example sub shell of 1s orbital is filled after the sub shell of 2s orbital occupied.

To learn more;

1. https://brainly.in/question/2826895
2. https://brainly.in/question/4551051