Question

The magnetic moments of Cu (Z = 29), Ti (Z = 22), and
Cr (Z = 24) are in the ratio of
(a) 1: √5 : 4 (b) 4 : √5 :1
(c) 1 :2:6 (d) 1: √3 : √21

Answer 1

The magnetic moments of Cu (Z = 29), Ti (Z = 22), and  Cr (Z = 24) are in the ratio of (c) 1 :2: 6

Explanation:

Magnetic moment = √n(n+2)    

n = number of unpaired electrons

Now we will calculate the number pf unpaired electrons.

Cu = [Ar] 3d¹⁰ 4s¹      n = 1  

Ti = [Ar] 3d² 4s²        n = 2

Cr = [Ar] 3d⁵ 4s¹        n = 6

Now we will calculate the magnetic moment.

For Cu:

√n(n+2)    

√1(1+2)  

√3 = 1.7

For Ti:

√n(n+2)    

√2(2+2)  

√8 = 2.8

For Cr:

√n(n+2)    

√6(6+2)  

√48 = 6.9

Answer 2

Explanation:

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