If n(A)=10,n(B)=12and n(AnB)=6, then find n(AUB)
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n(A U B) > = max (n(A), n(B)) = n(A) = 10.
Note that, we can also find the maximum possible value using n(A U B) =n(A) + n(B) - n(A intersection B), and upon using n(A intersection B) > = 0;, we have: n(A U B ) <= 10 + 6 - 0=16.
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