Question

If n(A)=25,n(B)=40,n(A∪B)=50 and n(B¹)=25,Find n(A∩B) and n(∪)​

Answer 1

Answer:

To find n(A∩B):-

n(A∪B)=n(A)+n(B)-n(A∩B)

50=25+40-n(A∩B)

50=65-n(A∩B)

50-65=n(A∩B)

n(A∩B)=15

n(B')=n(U)-n(B)

25=n(U)-40

25+40=n(U)

n(U)=65

Step-by-step explanation:

Hope it helps you

Answer 2

Answer:

kon'nichiwa

what is your name?

Step-by-step explanation:

nice to meet you (´･ω･`)