Math, asked by pranalikamble, 1 year ago

If n(A) = 3,n(B)=2 then find the total number of functions from A to B

Answers

Answered by aasthapurohit
3

Answer:

6

Step-by-step explanation:

If no of elements in set A is m and no of elements in set B is n then no of functions from A to B is m*n

Similarly here n(A) = 3

And n(B) = 2

Then no of functions from A to B is

3*2

6

Answered by pulakmath007
0

The total number of functions from A to B = 8

Given :

n(A) = 3 , n(B) = 2

To find :

The total number of functions from A to B

Concept :

The number of relations from a set with m elements to a set with n elements   \sf =  {n}^{m}

Solution :

Step 1 of 2 :

Write down number of elements in A and B

Here it is given that n(A) = 3 , n(B) = 2

Number of elements in A = n(A) = 3

Number of elements in B = n(B) = 2

Step 2 of 2 :

Calculate total number of functions from A to B

We know that number of relations from a set with m elements to a set with n elements   \sf =  {n}^{m}

By the given , m = 3 , n = 2

Hence total number of functions from A to B

\displaystyle \sf{ =  {2}^{3}   }

 = 8

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