If n(A) = 40, n(B) =35, n(AUB) =50, find n(A∩B)
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Answer:
Hence,
n(AUB) = n(U) - n(AUB)’
n(AUB) = 60 - 10
= 50
Now,
n(AUB) = n(A) + n(B) - n(A∩B)
so,
n(A∩B) = n(A) + n(B) - n(AUB)
= 35 + 24 - 50
= 9 is your answer
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