Question

If n(A-B) = 10 ,n (A intersection
B) = 5 and n (B-A) = 20,
then find n(B) and n(A union B)
​

Answer 1

Step-by-step explanation:

n(A union B) = n(A-B) + n(B-A) + n(A intersection

B) = 10 + 20 + 5 =35

n(B) = n(B-A) + n(A intersection B) = 20 + 5 =25

Answer 2

Answer:

n(A union B)

10 + 20 +5

=35

n(B)

35 = 10 + n(B)

-n(B) = 10 - 35

= 25