Math, asked by rajanpandey41957, 6 months ago

If n (A × B) = 48, n (B × C) = 64 and n (B) = 4, then n (A × C) =?​

Answers

Answered by pravalika21
0

Answer:

ANSWER

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

Answered By

pravalika 21

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