If n (A × B) = 48, n (B × C) = 64 and n (B) = 4, then n (A × C) =?
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n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
⇒n(A∩B)=16−14=2
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pravalika 21
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