if n(a intersection b)= 0 then (a union b) can be
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PLS MARK BRAINLIEST & ♥️⭐
Step-by-step explanation:
You must first make clear your premises. What do 0 and 1 mean in this context.
Set Elements:
Suppose we have set elements 0, 1. Then, this is nonsense because set C, an intersection, cannot have element 0 not found in the union D.
C = A intersect B = {0}
D = A union B = {1}
An Empty Set and Element 1:
Suppose we read the 0 as the “empty set symbol” and 1 as a set element. Then, we have something to say.
Set C says that there are no elements in A that also belong to B. That’s part of the definition of “intersection”.
Set D says at least one of the sets A, B must contain element 1.
Conclusion: Either set A or Set B, but not both, contains the element 1.
C = A intersect B = 0 (empty set)
D = A union B = {1}
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