Question

If 'n' identical liquid drops, each of radius 'r' and carries charge 'q' combines to form the big drop. Find total charge on big drop ​

Answer 1

Answer:For each small drop, V1=q4π∈0r

When n small drops coalesce to from oen big drop of radius R, then as

43πR3=n×43πr3,∴R=n1/3r

Total charge Q = nq

∴ Potential of big drop,

Vb=Q4π∈0R=nq4π∈0m1/3r

Vb=n2/3V,

Explanation:Hope it helps!!!