If n is a natural no. ,Then the average of n, n+1, n+2,n+3,n+4,n+5 is
Answers
Answered by
0
n+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)/6=n+n+1+n+2+n+3+n+4+n+5/6=6n+15/6
Similar questions