Question

If 'n' is a natural number, then 4n -3n ends with a digit x. the number of possible values of x is?

Answer 1

In this case 4n - 3n,

Let n = 1

∴ 4n - 3n = 4 - 3 = 1 ----------(1)

∵ 4n - 3n ends with x.

x = 1 ----------(2)

But we assumed that n = 1 ----------(3)

∴ From (2) and (3)

n = x

so for which ever value of n the answer is n.

So all the no.s are the possible values of x,

The main no.s are 0,1,2,3,4,5,6,7,8,9.

Hope you understood.

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Answer 2

Step-by-step explanation:

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