If n is a natural number, then 92n – 42n is always divisible by
a. 5 b. 13 c. both 5 and 13 d. None of these
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a. 5 because 92n - 42n = (92-42)n
= 50n
As 50 is divisible by 5, 50n is always divisible by 5
= 50n
As 50 is divisible by 5, 50n is always divisible by 5
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