Math, asked by swaminitesh23, 11 months ago

If n is a three digit number and last two digits
of square of n are 54 (n
2 = … 54), then how
many values of n are possible?

Answers

Answered by ineshmantri
0

Answer:

2n=54

n=54/2

n=27

that is the answer i know

Answered by elisaannaolaf03
0

Answer:

none

Step-by-step explanation:

For the square of a given number to end in 4, unit place of the given number should end in 2 or 8.

In general, for all 3 digit numbers ending in 2 or 8, the last 2 digits of its square would be 04, 24, 44, 64 and 84

Therefore, there are no numbers exist meeting the given criteria.

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