If n is an integer greater than 0, what is the remainder when 912n+3 is divided by 10?
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《2d+3》
912≡2mod10
n≡dmod 10 ,d=unit digit of n
912n≡2d mod10
912n+3
(i)≡(2d+3) mod10 if 1≤d≤3
(ii)≡10—(2d+3)≡7–2d,if 3<d<9
(iii)≡3 if d=0
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