distance between the point (3,1) and (0,x) is 5 units then the value of x is what
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The value of x is either 5 or -3. The end points are P(3,1) and Q(0,x).
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Answer:
√(3-0)^2+(1-x)^2=5
squaring on both sides
(3)2+(1-x)2=25
9+1+x2-2x=25
x2-2x-15=O
X2+3x-5x-15
x(x+3)-5(x+3)
(x+3)(x-5)
so value of x = -3 or 5
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