Math, asked by avahazarika5280, 9 months ago

If n is an integer, how many values of n will give an integral value of (16n^2+7n+6)/n ?

Answers

Answered by deepakkumarnwd8271
0

Answer:

Step-by-step explanation:

(16n^2+7n+6)/n

Let, n= 2, 3, 5, 6, 7, 9, 11, 13....... infinite.

Note:- The integer is a whole number as opposed to a fraction such as 3, 6, 8, 15. Integral means consisting of a whole number or an undivided quantity.

n= 2

(16n^2+7n+6)/n

= (16*2^2 + 7*2+6)/2

= (16*4 + 14+6)/2

again,

n = 3

(16n^2+7n+6)/n

= (16*3^2 + 7 * 3+6)/3

= (16*9 + 21 + 6)/3

= (144 + 27)/3

= 177/3

= 59

Such that you may check also when put the value of 'n'.

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