Question

If n is an integer such that the sum of the digit of n is 2 and 10^9<n<10^10.Find all the different values of n. ​

Answer 1

Answer:

There are 9 such numbers

110000000 ,101000000...10000001

and 200000000

Step-by-step explanation:

It is clear that number will be a 9 digit number. Since sum of digits is 2 all digits will be zero except (1,1) or (2,0) possible entries.

Now make such 9 digit numbers with two 1s or one "2"

Answer 2

Answer:

a)11

10000000001(first number)

now 1 can be placed in 9 other positions to give 9 numbers

20000000000 , one more number

total=1+9+1=11