Question

if n is an odd integer then show that n2-1 is divisible by 8

Answer 1

hey mate here is ur answer =

Odd integer are generally written as 2n+1.

replace n by 2n+1

we get =

(2n+1)^2-1=4n^2+1+4n-1=4n^2+4n

Divide it by eight =

4(n^2+n)/8=n(n+1)/2 which is sum of n natural numbers and it cant be a rational number hence it is always divisible.

hence proved ●●●

hope it helps.

✔✔be brainly ✔✔

✌

Answer 2

Answer:

Step-by-step explanation:

n2-1 =8

2n=8+1

2n =9