if n is an odd natural number , 3^(2n) + 2^(2n) is always divisible by
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Answered by
18
Solution:-
odd number are n = 1,3,5,7,9...............
given ,
3^(2n) + 2^(2n)
if n= 1 then,
3^2 + 2^2 = 9+4 = 13
if n= 3 the,
3^6+2^6 = 729 + 64 = 793
if n = 5
3^10 + 2^10 = 60,073
similarly
all numbers are 13 , 793, 60073
is divisible by 13
your right answer is option( A) = 13 ans
odd number are n = 1,3,5,7,9...............
given ,
3^(2n) + 2^(2n)
if n= 1 then,
3^2 + 2^2 = 9+4 = 13
if n= 3 the,
3^6+2^6 = 729 + 64 = 793
if n = 5
3^10 + 2^10 = 60,073
similarly
all numbers are 13 , 793, 60073
is divisible by 13
your right answer is option( A) = 13 ans
Answered by
6
Answer:
a) 13
Step-by-step explanation:
odd number are n = 1,3,5,7,9..
given ,
3^(2n) + 2^(2n)
if n= 1 then,
3^2 + 2^2 = 9+4 = 13
if n= 3 the,
3^6+2^6 = 729 + 64 = 793
if n = 5
3^10 + 2^10 = 60,073
similarly
all numbers are 13 , 793, 60073
is divisible by 13
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