Question

if n is even then prove that √(n-1) is irrational​

Answer 1

Answer:

Step-by-step explanation:

let us assume that √n-1 is rational no.

then there exist prome  a and b (b≠0)such that

√(n-1)=a/b

n-1=a^2/b^2   (squaring on both the sides)         (1)

(n-1)b^2=a^2

n-1 divides a^2

so n-1 divide a

let a =(n-1)c for some integer c putting n-1=c in (1) we get

(n-1)b^2 =2(n-1)⇒b^2=(n-1)c^2

⇒n-1 divides b^2

⇒n-1 divideb hence √n-1 is irrational

Answer 2

Answer:

sorry

Step-by-step explanation:

i couldn't answer