If n is odd, then (1 + 3 + 5 + 7 + ……. n terms) is equal to :
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let's take
1= 1²
1+3 = 4 (2²)
1+3+5= 9 (3²)
1+3+5+7=16 (4²)
Hence, for such n terms the sum has to be n²
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