Math, asked by subhendumohapatra, 11 months ago

If n is the sum of first 13968 prime numbers, the n is always divisible by
(a) 6
(b)4
(c)8
(d) none of these​

Answers

Answered by amitnrw
0

n is always divisible by none of these if n is the sum of first 13968 prime numbers

Step-by-step explanation:

n is the sum of first 13968 prime numbers

only 2 is the even prime numbers

Hence 13967 numbers will be odd

Sum of two odd numbers is even

sum of two even numbers is even

sum of odd & even number is odd

Hence sum of 13966 = (2 * 6983) odd numbers would be Even

then if 2 is added then

Sum will be even

now if 13967th odd number is added

then sum will be odd

Hence sum of  first 13968 prime numbers will be odd

hence sum of first 13968 prime numbers is not divisible by 2

Hence not divisible by  4, 6 or 8

Hence none of these is right answer

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