If n of a minus b is equals to 12 n of B minus a is equals to 15 then find n of a intersection section b
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Answer:
In △ABC AB=AC
⇒∠B=∠C (Angles opposite to equal sides are equal)
Now using angle sum property
∠A+∠B+∠C=180
∘
⇒80
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+∠C+∠C=180
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⇒2∠C=180
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−80
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⇒∠C=
2
100
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=50
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now ∠C+∠x=180
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(Angles made on straight line (AC) are supplementary)
⇒50
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+∠x=180
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⇒∠x=180
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−50
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=130
∘
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