If n[P(A)]=256 find n(A)
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Let A be a set
So, we know n(A) is called cardinal number of the set A which is equal to number of elements in set A and
p(A) is called power set of A.
Power set p(A) = set of all subsets of set A
We also know that,
If number of elements in set A = n then, n(A) = n
and Number of subsets of power set = 2^n
So equating values, we get
2^n = 256
2^n = 2^8
so, n = 8
Therefore, Number of elements in set A, n = 8
So, we know n(A) is called cardinal number of the set A which is equal to number of elements in set A and
p(A) is called power set of A.
Power set p(A) = set of all subsets of set A
We also know that,
If number of elements in set A = n then, n(A) = n
and Number of subsets of power set = 2^n
So equating values, we get
2^n = 256
2^n = 2^8
so, n = 8
Therefore, Number of elements in set A, n = 8
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Secondary SchoolMath5 points
If n[P(A)] = 256, find n(A)
Ask for details Follow Report by StarTbia17.06.2018
Answers
Rajpool007 Ambitious
N[P(A)]= 2^n(A)
therefore
256=2^8=2^n(A)
n(A)= 8
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2 votes
THANK
mysticd Genius
It is given that n[ P(A) ] = 256
********************************
If number of elements in
Set A = n( A ) = m
Number of elements in power
set of A = n[P(A] then
n[ P(A) ] = 2^m
**************************************
Here ,
2^m = n[ P(A)]
=> 2^m = 256 [ given ]
=> 2^m = 2^8
=> m = 8
[ Since , If a^p = a^q then p = q ]
Therefore ,
m = n( A ) = 8
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