Question

Three resistor of 10 ohm, 15 ohm , 20 ohm , are connected in series in a circuit . If the potential drop across the 15 ohm , resistor is 3 V, find the current in the circuit and potential drop across the 10 ohm resistor.

Answer 1

Here u go.....

R(1) = 10 ohm
R(2)= 15 ohm
R(3) = 20 ohm
V(2) = 3v
I = V/R
=3/15 = 0.2A
Since current in series circuit across each resistor remains same,
I = 0.2
Now,
R(1) = 10ohm
I = 0.2 A
V = I R
= 0.2(10) = 2 v.
Hence, current across circuit is 0.2 A and potential drop across 10 ohm resistor is 2v

Answer 2

HELLO THIS is your answer

Since resistors are connected in series effective resistance of the circuit= 10+15+20=45ohm

Now in series connection same current flows through each resistor

Therefore current in circuit => V=IR

3=I×15

I= 3/15= 0.2A

Now potential difference across 10ohm resistor=> V=IR = 0.2×10 = 2V

Hope it helps.......