Math, asked by thehonesty525, 2 days ago

If n(R)=32 , n(RUS)=57 and n(RnS)=15 then find n(S)?​

Answers

Answered by jitendra12iitg
1

Answer:

The answer is 40

Step-by-step explanation:

Given  

        n(R)=32, n(R\cup S)=57, n(R\cap S)=15

  • Using n(R\cup S)=n(R)+n(S)-n(R\cap S)\\

                     \Rightarrow 57=32+n(S)-15\\\Rightarrow 57=17+n(S)\\\Rightarrow n(S)=57-17=40

Answered by AllenGPhilip
11

Answer:

n(S) = 40

Step-by-step explanation:

Given:

n(R) = 32

n(R ∪ S) = 57

n(R ∩ S) = 15

n(S) = ?

n(R ∪ S) = n(R) + n(S) - n(R ∩ S)

57 = 32 +  n(S) - 15

57 = 17 +  n(S)

n(S) = 57 - 17 = 40

n(S) = 40

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