Subtract the sum of (8a-6a²+9) and (-10a-8+8a²) from -3
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Given:
(8a-6a²+9)
(-10a+8+8a²)
Step-by-step explanation:
Firstly, we will start with the summation of the given values ;
(8a-6a²+9) + (-10a-8+8a²)
Removing the brackets we get,
= 8a-6a²+9 - 10a-8+8a²
= -2a+2a²+1
By reforming the answer we get,
2a²-2a+1
Substracting the result from -3 we get,
-3 - (2a²-2a+1)
= -3 - 2a²+2a-1
= -2a²+2a-4
Therefore, the final result is -2a²+2a-4 after we have substracted the result of the summation from -3
Answer for the above question is, -2a²+2a-4
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