If n(U)=105, n(A)=60, n(B)=50, n(AUB)= 90 find n(A∩B) and n(AUB)complement, n0(A) and n0(B)
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Answer:
n( AnB) = { n(A) + n(B)- n ( AUB) }
= { 60+59- 90}
= { 119 - 90 }
= { 29 }
So, n ( AnB ) = 29
n ( AUB )' = { n ( U ) - n( AUB ) }
= { 105 - 90 }
= { 15}
So, n ( AUB )' = 15
n(A)' = ( n(U) - n(A))
= ( 90- 60)
= ( 30)
So, n(A)' = 30
n(B) ' = ( n(U) - n(B))
= 90 - 50
= 40
So, n(B)' = 40
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