Question

. If n(x)=50, n(A)=15, n(B)= 13 and n(ANB) = 10, find n(A'), n(B'), n(AUB) ​

Answer 1

Answer

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

Step-by-step explanation:

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