if n√x^p=x^m, then p is equal to
I) n ii) m iii)mn d)m/n
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(x+p)(x+q)−k=0
⟹x
2
+(p+q)x+pq−k=0
m and n are the roots of this equation
So, we have
Sum of roots =−(p+q)=m+n
Product of the roots =pq−k=mn
⇒pq=mn+k
Consider, (x−m)(x−n)+k=0
⇒x
2
−(m+n)x+mn+k=0
Sum of roots is m+n
But m+n=(−p)+(−q)
Product of the roots =mn+k
But mn+k=pq=(−p)(−q)
Hence, the roots of the new equation are −p,−q
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