Question

If n2 gas is bubbled through water at 293 k how many millimoles

Answer 1

Answer:

let the number of mole of N2 dissolved in water be n

Henry’s law constant for N2 at 293 K is 76.48 kbar.

according ti henrys law

partial pressure exerted by N2=Kh*x

x is the mole fraction

mole fraction of N2=x/(x+55.5)

.987=76.48*10^3 *x/(x+55.5)

x=.7 milimole