Question

if negavtive 1 and 2 are 2 zeros of the polynomial 2^3-x^2-5x-2 find its 3rd zeros

Answer 1

$\alpha = - 1 \: and \: \: \beta = 2 \\ 2 {x}^{3} - 2x^{2} - 5x - 2$
So,
$\alpha \beta \gamma = \frac{ - d}{a}$
$- 1 \times 2 \times \gamma = - \frac { - 2}{2} \\ - 2 \times \gamma = 1 \\ \gamma = \frac { - 1}{2}$
hope this will help you....