Question

If neutron, electron, proton and α-particle have same momentum (mv), then which of the following is correct?


All have same de-Broglie wavelength


All have same velocity


All have same kinetic energy


All have different de-Broglie wavelength

Answer 1

Explanation:

Electron has the largest de-Broglie wavelength, because de -Broglie wavelength is inversely proportional to the mass of the particle.

Answer 2

As we know that,

$wavelength = \frac{h}{p}$

where,

h = de-broglie's constant

p= linear momentum

According to the question, momentum is same for all the particles.

So,

h and p will remain constant in the equation. Therefore, wavelength will also remain same for all the particles because wavelength depends on the momentum of the particles.

Hence, option A is the correct answer.