If normal female and colourblindness male is married then which type of child is produced show in chekar board
Answers
Answered by
0
m assuming that by “normal” you mean “not color-blind”, and that you’re asking about whether the children will be color-blind or not.
Color-blindness is carried on the X chromosome. Men, being XY, will either be color-blind or not. Men cannot be carriers. Women, being XX, can be color-blind (if both X chromosomes carry the color-blindness gene), carriers (if only one of their X chromosomes carries the gene), or completely free of the gene.
So, we know that the woman is not color-blind, but that her father was. This means she is a carrier of the gene. She marries a man that is not color blind, and thus doesn’t carry the gene at all. If they have children:
If they have a son, that son will have a 50% chance to be color blind.
If they have a daughter, that daughter will have a 50% chance to be a carrier.
A woman cannot be color blind unless her father is color blind and her mother is either color-blind or a carrier. Since the father in this case is not color-blind, any daughters they have cannot be color-blind; at worst, they’ll be carriers.
As an example, my maternal grandfather was color-blind. My mother is a carrier, my father has normal color vision. I inherited color-blindness from my mother; that was a 50% chance, and it came up color-blind. My sister has a 50% to be free of the gene, and a 50% chance to be a carrier. We won’t know which way it went until/unless she has a son that is color blind. (Her husband isn’t color-blind, so if they have a son that isn’t color-blind, that could be mere chance, and any daughters they have will not be color-blind so we won’t be able to tell whether they’re carriers or free of the gene
Color-blindness is carried on the X chromosome. Men, being XY, will either be color-blind or not. Men cannot be carriers. Women, being XX, can be color-blind (if both X chromosomes carry the color-blindness gene), carriers (if only one of their X chromosomes carries the gene), or completely free of the gene.
So, we know that the woman is not color-blind, but that her father was. This means she is a carrier of the gene. She marries a man that is not color blind, and thus doesn’t carry the gene at all. If they have children:
If they have a son, that son will have a 50% chance to be color blind.
If they have a daughter, that daughter will have a 50% chance to be a carrier.
A woman cannot be color blind unless her father is color blind and her mother is either color-blind or a carrier. Since the father in this case is not color-blind, any daughters they have cannot be color-blind; at worst, they’ll be carriers.
As an example, my maternal grandfather was color-blind. My mother is a carrier, my father has normal color vision. I inherited color-blindness from my mother; that was a 50% chance, and it came up color-blind. My sister has a 50% to be free of the gene, and a 50% chance to be a carrier. We won’t know which way it went until/unless she has a son that is color blind. (Her husband isn’t color-blind, so if they have a son that isn’t color-blind, that could be mere chance, and any daughters they have will not be color-blind so we won’t be able to tell whether they’re carriers or free of the gene
Answered by
0
Answer:
When a color blind father and a mother who carries the color blind gene have children, there is a 50% chance that their sons will be color blind. Their daughters, however, will have a 50% chance of being color blind and 100% chance of being carriers of the gene.
Similar questions