If nth term of A.P is (2n+1),what is sum of first 5terms
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hey there..!!
given, nth term of AP= (2n+1).....(eq 1)
now, putting the value of n in eq1 as 1,we get
a1= 2+1=3. (i)
also,
a2= 2+1=5. (ii)
as well as,
a5=10+1=11.
from i and ii,
a2-a1=d=2
now,
sum of 5terms=
S=n/2 [2a+(n-1)*d]
=(5/2) [2*3+(5-1)*2]
=(5/2). [6+ 4*2]
=(5/2). [6+8]
=(5/2). 14
= 5*7
=35...(answer)
hope it will help.!
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