Question

If nth term of an AP is 4 +3n,find first two terms of AP

Answer 1

Tn=a+(n-1)d

Tn= 4+3n

a+(n-1)d=4+3n

Comparing both sides

d=3

Therefore, a+(n-1)3 =4+3n

a+3n-3= 4+3n

a=4+3+3n-3n

a=7

Now we have found that the first term of the AP is 7 and the common difference is 3

Therefore,

T2= 7+3

T2= 10

Therefore the first two terms of the AP are 7,10.

Answer 2

Answer:

a=7

Step-by-step explanation:

a2 = a+n-1×d

a2=7+2-1×3

a2=7+1×3=7+3

=10

a3=a+n-1×d

a3=7+(3-1)×3

a3=7+2×3

a3=7+6

=13