If nth term of AP is (2n+1) then the sum of tis first three terms is?
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Given that
an = 2n+1 ...(1)
put n=1 in (1), we get
a₁ = 2(1)+1 = 3
put n=2 in (1), we get
a₂ = 2(2)+1 = 5
put n=3 in (1), we get
a₃ = 2(3)+1 = 7
So a₁, a₂ and a₃ are three terms of an AP.
Hence sum of first three term of an AP is 3+ 5+ 7 = 15
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