if nth term of the sequence A. P is given by the Tn=5n+7 wirte down its common difference
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The nth term of the A.P. Is 5n+7
So
T1 is 5(1)+7=12
T2=5(2)+7=17
T3=5(3)+7=22
Now d=t2-t1
Thus d=17-12=5
Again d=t3-t2=22-17=5
Henceforth the common difference of the A.P. With nth term 5n+7 is 5.
Hope it helps!!
So
T1 is 5(1)+7=12
T2=5(2)+7=17
T3=5(3)+7=22
Now d=t2-t1
Thus d=17-12=5
Again d=t3-t2=22-17=5
Henceforth the common difference of the A.P. With nth term 5n+7 is 5.
Hope it helps!!
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