Question

If numerator is multiplied by 5 and 3 is subtracted from the denominator then the fraction obtained is 3 . Write the equation in standard form

Answer 1

lat the fraction be x/y
5x/ y-3=3
5x=3(y-3)
5x=3y -9
5x-3y=-9

Answer 2

The equation in standard form is $5x-3y+9=0$

Step-by-step explanation:

Let the numerator be x

let the denominator be y

Fraction $=[tex]\frac{x}{y}$[/tex]

numerator is multiplied by 5 and 3 is subtracted from the denominator

So, Fraction becomes =$\frac{5x}{y-3}$

We are given that the fraction obtained is 3

So, $\frac{5x}{y-3}=3$

$5x=3y-9$

$5x-3y+9=0$

Hence the equation in standard form is $5x-3y+9=0$

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