Question

if numerator of fraction is increased by 1,value becomes3/4.if its denominator is increased by 2,its value becomes 1/2.find fraction

Answer 1

$let \: numerator \: be \: x \\ denominator \: be \: y \\ \frac{x + 1}{y} = \frac{3}{4} \\ 4(x + 1) = 3y \\ 4x + 4 = 3y \\ 4x - 3y = - 4 \: (eq.1) \\ \frac{x}{y + 2} = \frac{1}{2} \\ 2x = y + 2 \\ y = 2x - 2(eq.2) \\ put \: value \: of \: y \: in \: eq.1 \\ 4x - 3(2x - 2) = - 4 \\4x - 6x + 6 = - 4 \\ - 2x = - 10 \\ x = 5 \\ put \: value \: of \: x \: in \: equation \: .1 \\ 4 \times 5 - 3y = - 4 \\ 20 - 3y = - 4 \\ 3y = 24 \\ y = 8 \\ the \: fraction \: is \: \frac{5}{8} \\ hope \: you \: like \: mark \: as \: brainliest$